# Sound pressure

Template:Sound measurements Sound pressure is the local pressure deviation from the ambient (average, or equilibrium) pressure caused by a sound wave. Sound pressure can be measured using a microphone in air and a hydrophone in water. The SI unit for sound pressure is the pascal (symbol: Pa). The instantaneous sound pressure is the deviation from the local ambient pressure p0 caused by a sound wave at a given location and given instant in time. The effective sound pressure is the root mean square of the instantaneous sound pressure over a given interval of time (or space). In a sound wave, the complementary variable to sound pressure is the acoustic particle velocity. For small amplitudes, sound pressure and particle velocity are linearly related and their ratio is the acoustic impedance. The acoustic impedance depends on both the characteristics of the wave and the medium. The local instantaneous sound intensity is the product of the sound pressure and the acoustic particle velocity and is, therefore, a vector quantity.

The sound pressure deviation p is

${\displaystyle p={\frac {F}{A}}\,}$

where

F = force,
A = area.

The entire pressure ptotal is

${\displaystyle p_{\mathrm {total} }=p_{0}+p\,}$

where

p0 = local ambient pressure,
p = sound pressure deviation.

## Sound pressure level

Sound pressure level (SPL) or sound level Lp is a logarithmic measure of the rms sound pressure of a sound relative to a reference value. It is measured in decibel (dB).

${\displaystyle L_{p}=10\log _{10}\left({\frac {p_{\mathrm {rms} }^{2}}{p_{\mathrm {ref} }^{2}}}\right)=20\log _{10}\left({\frac {p_{\mathrm {rms} }}{p_{\mathrm {ref} }}}\right){\mbox{ dB}}\,}$

where ${\displaystyle p_{\mathrm {ref} }}$ is the reference sound pressure and ${\displaystyle p_{\mathrm {rms} }}$ is the rms sound pressure being measured.[1]

Sometimes variants are used such as dB (SPL), dBSPL, or dBSPL. These variants are not permitted by SI.[2]

The commonly used reference sound pressure in air is ${\displaystyle p_{\mathrm {ref} }}$ = 20 µPa (rms), which is usually considered the threshold of human hearing (roughly the sound of a mosquito flying 3 m away). When dealing with hearing, the perceived loudness of a sound correlates roughly logarithmically to its sound pressure. See also Weber-Fechner law. Most measurements of audio equipment will be made relative to this level, meaning 1 pascal will equal 94 dB of sound pressure.

In other media, such as underwater, a reference level of 1 µPa is more often used.[3]

These references are defined in ANSI S1.1-1994.[4]

The unit dB (SPL) is often abbreviated to just "dB", which gives some the erroneous notion that a dB is an absolute unit by itself.

The human ear is a sound pressure sensitive detector. It does not have a flat spectral response, so the sound pressure is often frequency weighted such that the measured level will match the perceived level. When weighted in this way the measurement is referred to as a sound level. The International Electrotechnical Commission (IEC) has defined several weighting schemes. A-weighting attempts to match the response of the human ear to pure tones, while C-weighting is used to measure peak sound levels.[5] If the (unweighted) SPL is desired, many instruments allow a "flat" or unweighted measurement to be made. See also Weighting filter.

When measuring the sound created by an object, it is important to measure the distance from the object as well, since the SPL decreases in distance from a point source with 1/r (and not with 1/r2, like sound intensity). It often varies in direction from the source, as well, so many measurements may be necessary, depending on the situation. An obvious example of a source that varies in level in different directions is a bullhorn.

Sound pressure p in N/m² or Pa is

${\displaystyle p=Zv={\frac {J}{v}}={\sqrt {JZ}}\,}$

where

Z is acoustic impedance, sound impedance, or characteristic impedance, in Pa·s/m
v is particle velocity in m/s
J is acoustic intensity or sound intensity, in W/m2

Sound pressure p is connected to particle displacement (or particle amplitude) ξ, in m, by

${\displaystyle \xi ={\frac {v}{2\pi f}}={\frac {v}{\omega }}={\frac {p}{Z\omega }}={\frac {p}{2\pi fZ}}\,}$.

Sound pressure p is

${\displaystyle p=\rho c\omega \xi =Z\omega \xi ={2\pi f\xi Z}={\frac {aZ}{\omega }}=c{\sqrt {\rho E}}={\sqrt {\frac {P_{ac}Z}{A}}}\,}$,

normally in units of N/m² = Pa.

where:

Symbol SI Unit Meaning
p pascals sound pressure
f hertz frequency
ρ kg/m³ density of air
c m/s speed of sound
v m/s particle velocity
${\displaystyle \omega }$ = 2 · ${\displaystyle \pi }$ · f radians/s angular frequency
ξ meters particle displacement
Z = c • ρ N·s/m³ acoustic impedance
a m/s² particle acceleration
J W/m² sound intensity
E W·s/m³ sound energy density
Pac watts sound power or acoustic power
A m² Area

The distance law for the sound pressure p is inverse-proportional to the distance r of a punctual sound source.

${\displaystyle p\propto {\frac {1}{r}}\,}$ (proportional)
${\displaystyle {\frac {p_{1}}{p_{2}}}={\frac {r_{2}}{r_{1}}}\,}$
${\displaystyle p_{1}=p_{2}\cdot r_{2}\cdot {\frac {1}{r_{1}}}\,}$

The assumption of 1/r² with the square is here wrong. That is only correct for sound intensity.

Note: The often used term "intensity of sound pressure" is not correct. Use "magnitude", "strength", "amplitude", or "level" instead. "Sound intensity" is sound power per unit area, while "pressure" is a measure of force per unit area. Intensity is not equivalent to pressure.

${\displaystyle I\sim {p^{2}}\sim {\dfrac {1}{r^{2}}}\,}$

Hence ${\displaystyle p\sim {\dfrac {1}{r}}\,}$

### Examples of sound pressure and sound pressure levels

Sound pressure in air:

Source of sound Sound pressure Sound pressure level
pascal dB re 20 μPa
Theoretical limit for undistorted sound at
1 atmosphere environmental pressure
101,325 Pa 191 dB
Krakatoa explosion at 100 miles (160 km) in air 20,000 Pa 180 dB
Simple open-ended thermoacoustic device [6] 12,000 Pa 176 dB
M1 Garand being fired at 1 m 5,000 Pa 168 dB
Jet engine at 30 m 630 Pa 150 dB
Rifle being fired at 1 m 200 Pa 140 dB
Threshold of pain 100 Pa 130 dB
The Who live in concert 31st of May 1976 at 32 metres [7] 126 dB
Hearing damage (due to short-term exposure) 20 Pa approx. 120 dB
Jet at 100 m 6 – 200 Pa 110 – 140 dB
Jack hammer at 1 m 2 Pa approx. 100 dB
Hearing damage (due to long-term exposure) 6×10−1 Pa approx. 85 dB
Major road at 10 m 2×10−1 – 6×10−1 Pa 80 – 90 dB
Passenger car at 10 m 2×10−2 – 2×10−1 Pa 60 – 80 dB
TV (set at home level) at 1 m 2×10−2 Pa approx. 60 dB
Normal talking at 1 m 2×10−3 – 2×10−2 Pa 40 – 60 dB
Very calm room 2×10−4 – 6×10−4 Pa 20 – 30 dB
Leaves rustling, calm breathing 6×10−5 Pa 10 dB
Auditory threshold at 2 kHz 2×10−5 Pa 0 dB

Sound pressure in water:

Source of sound Sound pressure Sound pressure level
pascal dB re 1 μPa
Auditory threshold of a diver at 1 kHz 2.2 · 10-3 Pa 67 dB[8]

The formula for the sum of the sound pressure levels of n incoherent radiating sources is

${\displaystyle L_{\Sigma }=10\,\cdot \,{\rm {log}}_{10}\left({\frac {p_{1}^{2}+p_{2}^{2}+\cdots +p_{n}^{2}}{p_{\mathrm {ref} }^{2}}}\right)=10\,\cdot \,{\rm {log}}_{10}\left(\left({\frac {p_{1}}{p_{\mathrm {ref} }}}\right)^{2}+\left({\frac {p_{2}}{p_{\mathrm {ref} }}}\right)^{2}+\cdots +\left({\frac {p_{n}}{p_{\mathrm {ref} }}}\right)^{2}\right)}$

From the formula of the sound pressure level we find

${\displaystyle \left({\frac {p_{i}}{p_{\mathrm {ref} }}}\right)^{2}=10^{\frac {L_{i}}{10}},\qquad i=1,2,\cdots ,n}$

This inserted in the formula for the sound pressure level to calculate the sum level shows

${\displaystyle L_{\Sigma }=10\,\cdot \,{\rm {log}}_{10}\left(10^{\frac {L_{1}}{10}}+10^{\frac {L_{2}}{10}}+\cdots +10^{\frac {L_{n}}{10}}\right)\,{\rm {dB}}}$

### Beyond 191 dB

As sound pressure levels approach 191 dB in air at sea level, their waveforms become distorted; the exact level at which this happens varies with the barometric pressure. Sound waves are made up of rarefaction and compression cycles, but when the compression half of the wave cycle is double atmospheric pressure, the rarefaction half of the cycle approaches a perfect vacuum (no further air molecules to remove). At this point, the only possible increase in sound level that could be achieved is on the compression side of the waveform. (The rarefaction half of a sine wave would be clipped at any level above about 191 dB.) Any wave approaching these intensities is no longer considered sound, but a shock wave. Examples of such an occurrence are large-scale manned rocket launches, sonic booms, munitions explosions, thunder, earthquakes and volcanic explosions.

8. Parvin S.J., Searle S.L. and Gilbert M.J. (2001). "Exposure of divers to underwater sound in the frequency range from to 2250 Hz". Undersea Hyperb Med. Abstract. 28 (Supl). ISSN 1066-2936. OCLC 26915585. Retrieved 2008-05-05. Check date values in: |date= (help)